All the five digits numbers in which each suc | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

All the possible number are $^{9} \mathrm{C}_{5}$ (none containing the digit $0$ $)=126$

Total numbers starting with

$1 = {\,^8}{{\rm{C}}_4} = 7

Vedclass · Accepted Answer

$5$

Vedclass · Answer

All the possible number are $^{9} \mathrm{C}_{5}$ (none containing the digit $0$ $)=126$

Total numbers starting with

$1 = {\,^8}{{m{C}}_4} = 70$

${ 	ext { (using }2,3,4,5,6,7,8,9)} $

${	ext { Total starting with }}$

$\qquad 23 = {\,^6}{{m{C}}_3} = 20$

$(	ext { using } 4,5,6,7,8,9)$

${	ext { Total numbers starting with }} $

$\qquad 245 = {\,^4}{{m{C}}_2} = 6$

${m{ 9}}{{m{7}}^{th}}{m{  number }} = $

All the five digits numbers in which each successive digit exceeds its predecessor are arranged in the increasing order of their magnitude. The $97^{th}$ number in the list does not contain the digit:

Similar Questions

For a scholarship, atmost $n$ candidates out of $2n+1$ can be selected. If the number of different ways of selection of atleast one candidate for scholarship is $63$, then maximum number of candidates that can be selected for the scholarship is -

$^{20}C_1 + 3 ^{20}C_2 + 3 ^{20}C_3 + ^{20}C_4$ is equal to-

Find the number of words with or without meaning which can be made using all the letters of the word $AGAIN$. If these words are written as in a dictionary, what will be the $50^{\text {th }}$ word?

A lady gives a dinner party for six guests. The number of ways in which they may be selected from among ten friends, if two of the friends will not attend the party together is

The number of ways in which $21$ identical apples can be distributed among three children such that each child gets at least $2$ apples, is